Answer:
The diameter of the target is [tex]48\ in[/tex]
Step-by-step explanation:
we know that
In this problem the distance from the center of an archery target to the outside edge of the target is equal to the radius of the target
so
[tex]r=24\ in[/tex]
Remember that
The diameter is two times the radius
[tex]D=2r[/tex]
substitute
[tex]D=2(24)=48\ in[/tex]