Respuesta :
Given is :
Let the rate of walking in the evening be = x km/h
As Ed wants to walk at a rate if 1 km/h more in the morning, then rate in morning becomes = x+1 km/h
So, distance is 12 km, speed is x+1 km/h
Time = [tex]\frac{distance}{speed}[/tex]
Total time is = 5 h 24 m or convert it into hours, it becomes [tex]\frac{24}{60}=0.4[/tex] or 5.4 hours.
Time in morning becomes = [tex]\frac{12}{x+1}[/tex]
Time in evening becomes = [tex]\frac{12}{x}[/tex]
Now equation becomes,
[tex]\frac{12}{x+1}+\frac{12}{x}=5.4[/tex]
Solving this quadratic equation, we get, x= -5/9 or x=4
X cannot be negative so neglect -5/9.
Solving by using x=4, we get rate as x= 4+1 =5 km/h
Hence, rate in the morning is 5 km/h.
Answer:
His speed in the morning is=4.944 km/hr
Step-by-step explanation:
Ed is planning daily walking workouts on the same distance of 12 km in the morning and in the evening.
Usually he is walking at constant rate, however he planned his rate to be 1 km/h more in the morning than in the evening.
Let the speed in the evening is x km/hr.
so, the rate in the evening is x+1 km/hr.
he is willing to spend 5 hours and 24 minutes daily on these workouts.
i.e.
Total distance=24 km.
Total time=5 hours 24 minutes=5.4 hours.
As we know:
[tex]Average\ Speed=\dfrac{Total\ Distance}{Total\ Time}[/tex]
[tex]\dfrac{x+x+1}{2}=\dfrac{24}{5.4}\\\\x+\dfrac{1}{2}=4.444\\\\x=3.944[/tex]
Hence, speed in evening=3.944 km/hr.
speed in the morning is=4.944 km/hr.
