Answer:
see explanation
Step-by-step explanation:
Factor the numerators/ denominators where possible
x² + 7x + 10 = (x+ 2)(x + 5)
x² - 3x - 18 = (x - 6)(x + 3)
x² + x - 2 = (x + 2)(x - 1)
Hence
= [tex]\frac{(x+2)(x+5)}{x+3}[/tex] × [tex]\frac{(x-6)(x+3)}{(x+2)(x-1)}[/tex]
Cancel the factors (x + 2) and (x + 3) on numerator/denominator
= [tex]\frac{(x+5)(x-6)}{x-1}[/tex] ← in simplest form
The denominator of the product cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the value that x cannot be.
solve x - 1 = 0 ⇒ x = 1 ← restricted value
