Answer:
x2+4x+4=0
Step-by-step explanation:
To find the number of real roots for a quadratic, we apply the discriminant. The discriminant is the inside portion of the square root from the quadratic formula.
• [tex]b^2-4ac>0[/tex] yields 2 real roots
• [tex]b^2-4ac=0[/tex] yields 1 real root
• [tx]b^2-4ac<0[/tex] yields no real roots
x2+4x+4=0 has a = 1, b = 4 and c = 4. So 4^2 - 4(1)(4) is 16 - 16 = 0. This yields 1 root.
x2+x=0 has a = 1 and b = 1 and c = 0. So 1^2 - 4(1)(0) = 1- 0 = 1. This yields 2 roots.
x2-1=0 has a = 1 and b = 0 and c= -1. So 0^2 -4(1)(-1) = 0 + 4 = 4. This yields 2 roots.
