Answer:
[tex]a=0[/tex]
Step-by-step explanation:
The given expression is;
[tex](\frac{1}{7})^{3a+3} =343^{a-1}[/tex]
This implies that;
[tex]7^{-1(3a+3)} =7^{3(a-1)}[/tex]
Equate the exponents;
[tex]-1(3a+3) =3(a-1)[/tex]
Expand;
[tex]-3a-3 =3a-3[/tex]
[tex]-3a-3a =-3+3[/tex]
[tex]-6a=0[/tex]
[tex]a=0[/tex]
