Answer:
[tex]\large\boxed{(f+g)(x)=3x^2+x-1}[/tex]
Step-by-step explanation:
[tex](f+g)(x)=f(x)+g(x)\\\\\text{We have}\ f(x)=3x-1\ \text{and}\ g(x)=3x^2-2x.\\\\\text{Substitute:}\\\\(f+g)(x)=(3x-1)+(3x^2-2x)=3x-1+3x^2-2x\\\\(f+g)(x)=3x^2+(3x-2x)-1\\\\(f+g)(x)=3x^2+x-1[/tex]