The probability of choosing two green balls without replacing is 11/50 , and the probability of choosing one green ball is 12/25 . What is the probability of drawing a second green ball, given that the first ball is green


A. 7/10

B. 11/12

C. 11/24

D. 66/625

Respuesta :

Answer: C
Its easy conditional probability.
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Ver imagen ArianShiraz

The conditional probability of drawing a second green ball, given that the first ball is green is given by:

C. 11/24

What is Conditional Probability?

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which:

  • P(B|A) is the probability of event B happening, given that A happened.
  • [tex]P(A \cap B)[/tex] is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, we have that the events are as follows:

  • Event A: First ball is green.
  • Event B: Second ball is green.

The given probabilities are as follows:

[tex]P(A \cap B) = \frac{11}{50}, P(A) = \frac{12}{25} = \frac{24}{50}[/tex]

Hence, the conditional probability is given by:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{11}{50}}{\frac{24}{50}} = \frac{11}{24}[/tex]

Hence option C is correct.

More can be learned about conditional probability at https://brainly.com/question/14398287

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