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Two factory plants are making TV panels. Yesterday, Plant A produced
9000

panels. Six percent of the panels from Plant A and
1
%

of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was
4
%

?

Respuesta :

Answer:

Step-by-step explanation:

Alright, lets get started.

Plant A produced 9000 panels.

Suppose plant B produced x panels.

Number of defective panels plant A produced = [tex]9000*\frac{6}{100}=540[/tex]

Number of defective panels plant B produced = [tex]x*\frac{1}{100}=\frac{x}{100}[/tex]

Total defective panels = [tex]540 + \frac{x}{100}[/tex]

We are given that, overall percentage of defective panels from the two plants was 4%.

[tex](9000+x)\frac{4}{100}=540 + \frac{x}{100}[/tex]

[tex]360+\frac{4x}{100}=540+\frac{x}{100}[/tex]

[tex]\frac{3x}{100}=180[/tex]

Cross multiplying

[tex]x=\frac{180*100}{3}[/tex]

[tex]x=6000[/tex]

hence plant B produced 6000 panels.   :    Answer

Hope it will help :)