For this case, we must find the product of the following expressions:
[tex](-6a ^ 3b + 2ab ^ 2) (5a ^ 2-2ab ^ 2-b) =[/tex]
We apply distributive property:
[tex](-6a ^ 3b * 5a ^ 2) + (- 6a ^ 3b * -2ab ^ 2) + (- 6a ^ 3b * -b) + (2ab ^ 2 * 5a ^ 2) + (2ab ^ 2 * -2ab ^ 2) + (2ab ^ 2 * -b) =[/tex]
When multiplying powers with the same base, the same base is put and the exponents are added.
[tex]-30a ^ 5b + 12a ^ 4b ^ 3 + 6a ^ 3b ^ 2 + 10a ^ 3b ^ 2-4a ^ 2b ^ 4-2ab ^ 3 =[/tex]
We add similar terms:
[tex]-30a ^ 5b + 12a ^ 4b ^ 3 + 16a ^ 3b ^ 2-4a ^ 2b ^ 4-2ab ^ 3[/tex]
Answer:
[tex]-30a ^ 5b + 12a ^ 4b ^ 3 + 16a ^ 3b ^ 2-4a ^ 2b ^ 4-2ab ^ 3[/tex]