For this case we must find the product of two mixed numbers:
[tex]3 \frac {1} {3} = 3 + \frac {1} {3} = \frac {9 + 1} {3} = \frac {10} {3}\\5 \frac {1} {4} = 5 + \frac {1} {4} = \frac {20 + 1} {4} = \frac {21} {4}[/tex]
So, we have:
[tex]\frac {10} {3} * \frac {21} {4} = \frac {10 * 21} {3 * 4} = \frac {210} {12} = \frac {105} {6} = \frac {35} {2}[/tex]
If we go to a mixed number we have:
[tex]\frac {35} {2} = 17 \frac {1} {2}[/tex]
Answer:
[tex]17 \frac {1} {2}[/tex]
