Can I get some help on how to solve this?

Answer:
see explanation
Step-by-step explanation:
Factorise both denominators
x² + 2x = x(x + 2) ← common factor of x
x² - 4 = (x - 2)(x + 2) ← difference of squares
Before subtracting we require common denominators
Multiply the numerator/denominator of the first fraction by (x - 2)
Multiply the numerator of the second fraction by x
= [tex]\frac{5}{x(x-2)(x+2)}[/tex] - [tex]\frac{2x}{x(x-2)(x+2)}[/tex]
Distribute and simplify the numerator leaving the denominator
= [tex]\frac{5x-10-2x}{x(x-2)(x+2)}[/tex]
= [tex]\frac{3x-10}{x(x-2)(x+2)}[/tex]