Answer:
Area of ABCD = 50 square units
Area of IJKL = 80 square units
Area of QRST = 100 square units
Area of UVWX = 300 square units
Step-by-step explanation:
ABCD: A (-9 , 8) , B (-5 , 5) , C (1 , 13) , D (-3 , 16)
AB = √(-5 - -9)² + (5 - 8)² = 5
BC = √(1 - -5)² + (13 - 5)² = 10
Area = 5 × 10 = 50 square units
IJKL: I (-6 , 2) , J (2 , 2) , K (2 , -8) , L (-6 , -8)
IJ = 2 - -6 = 8 ⇒ horizontal line (same y-coordinates)
JK = 2 - -8 = 10 ⇒ vertical line (same x-coordinates)
Area = 8 × 10 = 80 square units
QRST: Q (10 , 0) , R (15 , 5) , S (25 , -5) , T (20 , -10)
QR = √(15 - 10)² + (5 - 0)² = 5√2
RS = √(25 - 15)² + (-5 - 5)² = 10√2
Area = 5√2 × 10√2 = 100 square units
UVWX: U (0 , 5) , V (15 , 20) , W (25 , 10) , X (10 , -5)
UV = √(15 - 0)² + (20 - 5)² = 15√2
VW = √(25 - 15)² + (10 - 20)² = 10√2
A = 15√2 × 10√2 = 300 square units
Answer:
Step-by-step explanation:
Area of any rectangle = length x width
Using this:
ABCD: Length [tex]= AB=\sqrt{(-5 - -9)² + (5 - 8)²} = 5[/tex]
Width =
BC = [tex]\sqrt{(1 - -5)² + (13 - 5)²} = 10[/tex]
Area =50 sq units
Similarly for EFGH, length =width = [tex]9\sqrt{2}[/tex]
Area = 162 sq units.
iJKL:
Length = 8 and width = 10
Area = 80 sq units.
MNOP:
Length = width =6
Area = 36 sq units.
QRST: 100 sq units and
TUVW: 300 sq units.
