A shark is swimming at 10 m/s west when it spots some floating bait caught in some seaweed straight ahead. After 10 s, and traveling at a velocity of 15 m/s, the shark reaches the bait. What was the shark's average acceleration? A. 0.5 m/s² B. 0.5 m/s² east C. 0.5 m/s² west D. 10 m/s²

Respuesta :

Answer:

C. 0.5 m/s² west

Explanation:

The shark's average acceleration is given by:

[tex]a=\frac{v-u}{t}[/tex]

where

v = 15 m/s west is the final velocity

u = 10 m/s west is the initial velocity

t = 10 s is the time taken

Substituting data into the equation, we find:

[tex]a=\frac{15 m/s-10 m/s}{10s}=0.5 m/s^2[/tex]

and since the acceleration is positive, it means that it is in the same direction as the velocity, so west.

Answer:

The average acceleation is 0.5 m/s² west

Explanation:

As we know that

Acceleration =  [tex]\frac{Final velocity - Initial velocity}{time}[/tex]

Putting the values

Acceleration = [tex]\frac{20-10}{10}[/tex]

Acceleration = 0.5

Since the shark was moving in west so the Acceleration will be in west too