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Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mph and if Car 2 averages 50 mph, how far apart will they be after Car 1 has traveled 3.5 hours?
A:230
B:250
C:210

Respuesta :

Answer:

C. 210 miles.

Step-by-step explanation:

If Car 1 left 30 minutes earlier

than Car 2 therefore Car 2 traveled 3 hours

compared to Car 1's 3.5 hours

Car 1 traveled 3.5 x 42 mph = 147 miles

Car 2 travelled 3 x 50 mph = 150 miles

The distance between them would be  

√147^2 + 150^2

= 210

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