The answer of this question in the picture

Answer:
ooooh he cheatingg
Step-by-step explanation:
answer is on the paper isnt it lool?
Answer:
see explanation
Step-by-step explanation:
Note that
sin60° = [tex]\frac{\sqrt{3} }{2}[/tex], cos60° = [tex]\frac{1}{2}[/tex]
Using trig. ratios in the right triangle
sin60° = [tex]\frac{opp}{hyp}[/tex] = [tex]\frac{x}{18}[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex] ( cross- multiply )
2x = 18[tex]\sqrt{3}[/tex] ( divide both sides by 2)
x = [tex]\frac{18\sqrt{3} }{2}[/tex] = 9[tex]\sqrt{3}[/tex]
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cos60° = [tex]\frac{adj}{hyp}[/tex] = [tex]\frac{y}{18}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
2y = 18 ( divide both sides by 2 )
y = 9