Read the statement.

A 200 mL NaCl solution with a concentration of 4.0 g/L is mixed with a 600 mL solution containing 8% NaCl (m/v).

What is the final concentration of salt in the solution in g/L?

A.4.7
B.61
C.6.1
D.47

Question

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Respuesta :

itscarsonbusiness itscarsonbusiness · Answer 1 · 2019-03-07T22:58:05+01:00

BRAINLIEST

It is D due to the 200 - 4.0 divided by the 8% of NaCI

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Alleei Alleei · Answer 2 · 2019-08-19T09:25:36+02:00

Answer : The correct option is, (B) 61 g/L

Explanation :

First we have to calculate the mass of NaCl.

As, 1000 ml NaCl solution contain 4 grams of NaCl

So, 200 ml NaCl solution contain [tex]\frac{200}{1000}\times 4=0.8[/tex] grams of mass of NaCl

Now we have to calculate the mass of another NaCl.

As, 100 ml NaCl solution contain 8 grams of NaCl

So, 600 ml NaCl solution contain [tex]\frac{600}{100}\times 8=48[/tex] grams of NaCl

Total mass of NaCl = 0.8 + 48 = 48.8 g

Total volume of NaCl solution = 200 + 600 = 800 ml

Now we have to calculate the final concentration of salt in the solution.

[tex]Concentration=\frac{\text{Total mass}}{\text{Total volume}}[/tex]

[tex]Concentration=\frac{48.8g}{800ml}=0.061g/ml=0.061g/ml\times 1000=61g/L[/tex]

Therefore, the final concentration of salt in the solution is, 61 g/L