Although I am not clear as to whether the radius is r—1 or otherwise, but if i work with the values i see then:
Volume — T. S. A.
= πr²h — (2πr²+2πrh)
So after the simplification, I substitute the values given,
r= r—1 and h=h—1
And the answer is...
π(r—1)(rh—3r—3h+5)!