Respuesta :

Kamikazeminem

[tex]Answer: \\ 8 {x}^{2} + 16x + 8 = 0 \\ \Leftrightarrow 8({x}^{2} + 2x + 1) = 0 \\ \Leftrightarrow {x}^{2} + 2x + 1 = 0 \\ \Leftrightarrow {(x + 1)}^{2} = 0 \\ \Leftrightarrow x + 1 = 0\Leftrightarrow x = - 1 \\ \Rightarrow B[/tex]

Answer: -1

Step-by-step explanation:

8(-1)^2+16(-1)+8=0

8-16+8=0

0=0

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