Answer:
The measure of arc GE is [tex]25\°[/tex]
Step-by-step explanation:
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
In this problem
m<A is a external angle
so
[tex]m<A=\frac{1}{2}(arc\ CD-arc\ GE)[/tex]
substitute the values and solve for the measure of arc GE
[tex]15\°=\frac{1}{2}(55\°-arc\ GE)[/tex]
[tex]30\°=(55\°-arc\ GE)[/tex]
[tex]arc\ GE=55\°-30\°=25\°[/tex]
