(-4y^4 +5y^2+30y+49)÷(2y–5)

Answer:
[tex]-2y^{3} -5y^{2}-10y-10 -\frac{1}{2y-5}[/tex]
Step-by-step explanation:
To perform the division we need to write the polynomial in descending order with all missing coefficients (if any), thus, the original polynomial is written as the following:
[tex]-4y^{4}+0y^{3}+5y^{2}+30y+49[/tex]
The attached picture reveals the whole procedure to obtain the following:
[tex]-2y^{3} -5y^{2}-10y-10 -\frac{1}{2y-5}[/tex]
Remember, the term remaining after the last subtract step is the remainder and must be written as a fraction in the answer.