The table represents a linear equation.which equation shows how (-10,8) can be used to write the equation of this line is point-slope form?

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gmany gmany · Answer 1 · 2019-03-12T23:18:32+01:00

Answer:

[tex]\large\boxed{y-8=-0.2(x+10)}[/tex]

Step-by-step explanation:

The point-slope form of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

m - slope

(x₁, y₁) - point

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

From the table we have the points (-10, 8) and (10, 4). Substitute:

[tex]m=\dfrac{4-8}{10-(-10)}=\dfrac{-4}{20}=-\dfrac{1}{5}=-0.2[/tex]

The equation of a line:

[tex]y-8=-0.2(x-(-10))\\\\y-8=-0.2(x+10)[/tex]

rmanquelafquen rmanquelafquen · Answer 2 · 2019-09-04T15:46:39+02:00

Answer:

The answer is [tex]y-8=-0.2*(x+10)\\\\[/tex]

Step-by-step explanation:

In order to determine the correct option, we have to know about point-slope form.

The point-slope form is the way that we can create linear functions from a point and a slope. The formula is:

[tex]y-y_1=m*(x-x_1)\\\\\\\\[/tex]

Where:

[tex](x_1,y_1)\\\\[/tex]: Coordinates of the point.

m: Slope

Also we can get the slope from two points. The formula is:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex](x_1,y_1)\\\\[/tex]: Coordinates of the first point.

[tex](x_2,y_2)\\\\[/tex]: Coordinates of the second point.

So first we determine the slope:

[tex]P_1=(x_1,y_1)=(-10,8)\\P_2=(x_2,y_2)=(-5,7)\\\\m=\frac{7-8}{-5-(-10)}\\m=\frac{-1}{5}=-0.2\\\\\\[/tex]

Finally, the correct option is:

[tex]y-8=-0.2*(x+10)\\\\[/tex]