Respuesta :

kudzordzifrancis

Answer:

[tex](x-3)^2=18[/tex]

Step-by-step explanation:

The given equation is;

[tex]x^2-6x-9=0[/tex]

Group the constant on the Right Hand Side.

[tex]x^2-6x=9[/tex]

Add half the square of the coefficient of [tex]x[/tex] to both sides.

[tex]x^2-6x+(-3)^2=9+(-3)^2[/tex]

The left hand side is now a perfect square.

[tex](x-3)^2=9+9[/tex]

[tex](x-3)^2=18[/tex]

zainebamir540

Answer:

(x-3)² = 18

Step-by-step explanation:

We have given an equation.

x²-6x-9 = 0

We have to find the equation after completing square.

Adding 9 to both sides of above equation, we have

x²-6x-9+9 = 0+9

x²-6x = 9

Adding half of the term -6 to both sides of above equation, we have

x²-6x+(-3)² = 9+(-3)²

(x-3)²  =  9+9

(x-3)² = 18 which is the answer.

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