Answer:
The rate at which the friction slows down the object is [tex] 2.5 ms^{-2}[/tex]
Step-by-Step Explanation:
Mass of the object = 12 kg
Opposing Force of friction = F = 30 N
The rate at which the friction slows down the object is actually the deceleration produced by that force.
According to Newton's law:
F = ma
So the acceleration/deceleration produced by a Force F on an object of mass m is a, given by:
a = F/m
Hence deceleration produced by friction = a = 30/12
[tex]a = 2.5 ms^{-2}[/tex]
