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The methyl red solution you will use for this experiment was made using .080 grams of methyl red per liter of solution. The molar mass of methyl red is 269.31 g/mole. What is the molarity of the stock solution you will be using?

Respuesta :

1. Calculate # Moles Methyl red:

[tex]\frac{0.080g}{}*\frac{1 mol}{269.31g} = 2.97 * 10^-4[/tex] moles

2. Calculate the Molarity: f

Molarity = [tex]\frac{2.97*10^-4mol}{1\l} = 2.97*10^-4 \ M[/tex]

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