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The volume of gas in a ballon is 1.90L at 21.0C. The balloon is heated, causing it to expand to a volume of 5.70L. What is the new temperature of the gas into the ballon

Respuesta :

jacob193

New temperature:

  • 882.45 K, which is the same as
  • 609.3 °C.

Explanation

By Charles's Law,

[tex]V \propto T[/tex],

where

  • V is the volume of an ideal gas, and
  • T is the absolute temperature of the gas.

In other words,

[tex]\dfrac{V_2}{V_1} = \dfrac{T_2}{T_1}[/tex],

[tex]T_2 = T_1\cdot\dfrac{V_2}{V_1}[/tex]

[tex]T_1 = 21.0\;\textdegree{}\text{C}=(21.0 + 273.15)\;\text{K}[/tex].

[tex]T_2 =T_1\cdot\dfrac{V_2}{V_1} = (21.0 + 273.15)\;\text{K}\times\dfrac{5.70\;\text{L}}{1.90\;\text{L}}=882.45\;\text{K}[/tex].

[tex]882.45\;\text{K} = (882.45 - 273.15)\;\textdegree{}\text{C}=609.3\;\textdegree{}\text{C}[/tex].

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