Answer:
C
Step-by-step explanation:
Rearrange the quadratic into standard form by subtracting d from both sides
- 16t² + 8t - d = 0 ← in standard form
with a = - 16, b = 8, c = - d
Using the quadratic formula to solve for t
t = (- 8 ± [tex]\sqrt{8^2-(4(-16)(-d))}[/tex] )/ - 32
= ( - 8 ± [tex]\sqrt{64-64d}[/tex] )/ - 32
= ( - 8 ± [tex]\sqrt{64(1-d)}[/tex]) / - 32
= ( - 8 ± 8[tex]\sqrt{1-d}[/tex]) / - 32
= [tex]\frac{-8}{-32}[/tex] ± [tex]\frac{8}{32}[/tex][tex]\sqrt{1-d}[/tex]
= [tex]\frac{1}{4}[/tex] ± [tex]\frac{1}{4}[/tex][tex]\sqrt{1-d}[/tex]
= [tex]\frac{1}{4}[/tex] ± [tex]\frac{\sqrt{1-d} }{4}[/tex]
