Respuesta :
Answer:
The 66th term of given sequence is 589.
Step-by-step explanation:
We have given a arithmetic sequence.
4,13,22,31
We have to find 66th term of given sequence.
The formula to find nth term of the arithmetic sequence:
aₙ = a₁+(n-1)d where d is the common difference.
d = 13-4 = 9
Putting n = 66,a₁ = 4 and d = 9 in given formula, we have
a₆₆ = 4+(66-1)(9)
a₆₆ = 4+(65)9
a₆₆ = 4+585
a₆₆ = 589 which is the answer.
Answer:
[tex] a_{66} [/tex] = 589
Step-by-step explanation:
We are given the following arithmetic sequence and we are to find it 66th term:
4, 13, 22, 31
We know the formula for the arithmetic sequence which is:
[tex]a_n=a_1(n-1)d[/tex]
where [tex]n[/tex] is the number of the term,
[tex]a_1[/tex] is the first term; and
[tex]d[/tex] is the difference between two terms.
Substituting the given values in the above formula to get:
[tex]a_{66}=4+(66-1)9[/tex]
[tex]a_{66}=4+(65)9[/tex]
[tex]a_{66}=4+585[/tex]
[tex]a_{66}=589[/tex]