Respuesta :

Answer:

The 66th term of given sequence is 589.

Step-by-step explanation:

We have given a arithmetic sequence.

4,13,22,31

We have to find 66th term of given sequence.

The formula to find nth term of the arithmetic sequence:

aₙ = a₁+(n-1)d where d is the common difference.

d = 13-4 = 9

Putting n = 66,a₁ = 4 and d = 9 in given formula, we have

a₆₆ = 4+(66-1)(9)

a₆₆ = 4+(65)9

a₆₆ = 4+585

a₆₆ = 589 which is the answer.

Answer:

[tex] a_{66} [/tex] = 589

Step-by-step explanation:

We are given the following arithmetic sequence and we are to find it 66th term:

4, 13, 22, 31

We know the formula for the arithmetic sequence which is:

[tex]a_n=a_1(n-1)d[/tex]

where [tex]n[/tex] is the number of the term,

[tex]a_1[/tex] is the first term; and

[tex]d[/tex] is the difference between two terms.

Substituting the given values in the above formula to get:

[tex]a_{66}=4+(66-1)9[/tex]

[tex]a_{66}=4+(65)9[/tex]

[tex]a_{66}=4+585[/tex]

[tex]a_{66}=589[/tex]