Identify AC rounded to the nearest tenth. HELP ASAP!!

Answer:
Step-by-step explanation:
Use sine:
[tex]sine=\dfrac{opposite}{hypotenuse}[/tex]
We have
[tex]opposite=8\\hypotenuse=AC\\\alpha=43^o\\\\\sin43^o\approx0.682[/tex]
Substitute:
[tex]\dfrac{8}{AC}=0.682[/tex]
[tex]\dfrac{8}{AC}=\dfrac{682}{1,000}[/tex] cross multiply
[tex]682AC=8,000[/tex] divide both sides by 682
[tex]AC=\dfrac{8,000}{682}[/tex]
[tex]AC\approx11.7[/tex]