Answer:
[tex]a_{12}[/tex] = [tex]\frac{1}{8}[/tex]
Step-by-step explanation:
Given the terms
256, 128, 64, 32
These are the terms of a geometric sequence with common ratio r and
n th term = a[tex](r)^{n-1}[/tex] ← a is the first term
here r = [tex]\frac{128}{256}[/tex] = [tex]\frac{64}{128}[/tex] = [tex]\frac{1}{2}[/tex] and a = 256
Hence
[tex]a_{12}[/tex] = 256 × [tex](\frac{1}{2}) ^{11}[/tex]
= 256 × [tex]\frac{1}{2048}[/tex] = [tex]\frac{1}{8}[/tex]
