Joey has 24 coins in his pocket. The coins are all nickels and dimes. The total value of the coins is $1.85. How many dimes does Joey have? Which of the following systems is correct for this situation?
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Joey has 24 coins in his pocket The coins are all nickels and dimes The total value of the coins is 185 How many dimes does Joey have Which of the following sys class=

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Answer:

Your system of equation:

n + d = 24

5n + 10d = 185

Step-by-step explanation:

Let:

nickels = $0.05; amount of dimes = n

dimes = $0.10; amount of dimes = d

There are 24 coins in all:

n + d = 24

Note the amount each coin is worth. The total value is $1.85

0.05n + 0.10d = 1.85

Move the decimal point to the right for each term.

0.05n = 5n

0.10d = 10d

1.85 = 185

5n + 10d = 185 is your new equation.

Your system of equation:

n + d = 24

5n + 10d = 185

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Answer with Step-by-step explanation:

1 nickel = $ 0.05

Let there be n nickels

n nickels= $ 0.05n

1 dimes = $ 0.10

Let there be d dimes

d dimes= $ 0.10d

Joey has 24 coins in his pocket.

n+d=24

The total value of the coins is $1.85.

0.05n+0.10d=1.85

Multiplying by 100 on both sides, we get

5n+10d=185

Hence, system of equation are:

n+d=24

5n+10d=185

d=24-n

Putting it in 5n+10d=185

5(24-n)+10d=185

120-5n+10d=185

5d=65

d=13

Hence, Joey has 13 dimes