Answer:
Step-by-step explanation:
"12 more than the quiotent of a number n of and two decreased by 4"
[tex]\left(\dfrac{n}{2}-4\right)+12[/tex]
Simplify:
[tex]\left(\dfrac{n}{2}-4\right)+12=\dfrac{n}{2}-4+12=\dfrac{n}{2}+8[/tex]
Put n = 4 to the expresssion:
[tex]\dfrac{4}{2}+8=2+8=10[/tex]