Answer:
There are infinite solutions for your problem. Here is a set of solutions:
a............. { 2x + 5 = y }
{ 3x + 2y = 1 }
b............. { x + 2y = y }
{ -7x + y = 0 }
c............. { 6z + 2y = -9 }
{ -z - 2y = 5 }
d............. { m + 2 = -3n }
{ -7n + 3m = 2 }
Step-by-step explanation:
Linear equations are the ones that can be represented by a line (straight line)
These are equations of the form
y = a*x + b (1)
Where a and b are real numbers.
This means that the answer to your 4 part question can be any number that satisfies equation (1)
As long as your answer consists of two real numbers (integers, rational, irrational..) any combination you place will be correct.
For your answer in particular, I select random integers numbers from -9 to 9 to fill the blanks.
You also need to bare in mind the variables used in the set of equations [(x,y) or (m,n) or (z,y)]
For example
Part a
............. { 2x + 5 = y }
{ 3x + 2y = 1 }
Part b
............. { x + 2y = y }
{ -7x + y = 0 }
Part c
............. { 6z + 2y = -9 }
{ -z - 2y = 5 }
Part d
............. { m + 2 = -3n }
{ -7n + 3m = 2 }
