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Write the equilibrium-constant expression for the reaction a(s)+3b(l)↽−−⇀2c(aq)+d(aq) in terms of [a], [b], [c], and [d] as needed. note that kc, which is sometimes symbolized as keq, denotes that the equilibrium constant is expressed using molar concentrations. for this question, kc means the same thing as keq.

Respuesta :

Answer:

K = [tex]\frac{[c]^{2}[d]}{1}=[c]^{2}[d][/tex]

Explanation:

In equilibrium constant expression

a) we write the concentration of the products on the upper side divided by the concentration of reactants

b) the concentration terms are raised to the coefficient which are in the chemical reaction.

c) we do not consider the concentration of solids or liquids in an aqueous phase reaction

d) we do not consider the concentration of solids / liquids / aqueous phase in a gas phase reaction

Here

The coefficient of A(s) = 1 , however it will not be considered in the expression as it is solid.

The coefficient of B(l) = 3 , will not consider it

coefficient of c = 2

coefficient of d = 1

The expression will be:

K = [tex]\frac{[c]^{2}[d]}{1}=[c]^{2}[d][/tex]

dsdrajlin

The expression of the equilibrium constant for the reaction

a(s) + 3b(l) ⇄ 2 c(aq) + d(aq) is:

[tex]Kc = [c]^{2} [d][/tex]

Let's consider the following reaction at equilibrium.

a(s) + 3b(l) ⇄ 2 c(aq) + d(aq)

The equilibrium constant (Kc) is the ratio of the concentration of products to the concentration of the reactants, each raised to their respective stoichiometric coefficients. It only includes gases and aqueous species. Solids and pure liquids are neglected because their activities are close to 1.

The equilibrium constant for this reaction is:

[tex]Kc = [c]^{2} [d][/tex]

The expression of the equilibrium constant for the reaction

a(s) + 3b(l) ⇄ 2 c(aq) + d(aq) is:

[tex]Kc = [c]^{2} [d][/tex]

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