Can someone please help me

[tex]Answer: \\ Zeros:0 = - 2 {(x - 2)}^{2} + 6 \\ \Leftrightarrow 2 {(x - 2)}^{2} = 6 \\ \Leftrightarrow {(x - 2)}^{2} = 3 \\ \Leftrightarrow x - 2 = \pm \sqrt{3} \\ \Leftrightarrow x = 2\pm \sqrt{3} \\ \Rightarrow D. \: Zeros \: at \: x = 2\pm \sqrt{3}[/tex]