x^2+2x+9=0 please?!

Answer:
D
Step-by-step explanation:
Given a quadratic equation in standard form : ax² + bx + c = 0
We can solve for x using the quadratic formula
x² + 2x + 9 = 0 ← is in standard form
with a = 1, b = 2 and c = 9
x = ( - 2 ± [tex]\sqrt{2^2-(4(1)(9)}[/tex]) / 2
= ( - 2 ± [tex]\sqrt{4-36}[/tex]) / 2
= (- 2± [tex]\sqrt{-32}[/tex]) / 2)
= (- 2 ± [tex]\sqrt{16(2)(-1)}[/tex]) / 2
= ( - 2 ± 4i[tex]\sqrt{2}[/tex]) / 2
= [tex]\frac{-2}{2}[/tex] ± [tex]\frac{4i\sqrt{2} }{2}[/tex]
= - 1 ± 2i[tex]\sqrt{2}[/tex] → D
Answer:
Choice D is the answer.
Step-by-step explanation:
We have given a quadratic equation.
x²+2x+9 = 0
We have to find the solution of given equation.
From given equation, a = 1, b = 2 and c = 9.
x = (-b±√b²-4ac) / 2a is quadratic formula to find the solve quadratic equation.
Putting given values in formula, we have
x = (-2±√(2)²-4(1)(9) ) / 2(1)
x = (-2±√4-36) / 2
x = (-2±√-32) / 2
x = (-2±√16√-2 ) /2
x = (-2±4√2√-1) / 2 ∵ i = √-1
x = 2(-1±2√2i) / 2
x = -1±2√2i is the solution of given solution.