Find the indicated probability.
The table below describes the smoking habits of a group of asthma sufferers.
Nonsmoker Occasional, smoker Regular, smoker Heavy, smoker Total
Men 334, 50, 68, 32, 484
Women 357, 30, 89, 37, 513
Total 691, 80, 157, 69, 997


a) If one of the 997 people is randomly selected, find the probability of getting a woman or nonsmoker.
b) If a person is selected at random, what is the probability of getting a woman?
c) If a person is selected at random, what is the probability of getting a man and a non smoker?
d) If a person is selected at random, what is the probability of getting a woman and heavy smoker?
e). If one of the 997 people is randomly selected, find the probability of getting a man or heavy smoker.

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Answer:

a) [tex]P_1=\dfrac{847}{997}.[/tex]

b) [tex]P_2=\dfrac{513}{997}.[/tex]

c) [tex]P_3=\dfrac{334}{997}.[/tex]

d) [tex]P_4=\dfrac{37}{997}.[/tex]

e) [tex]P_5=\dfrac{521}{997}.[/tex]

Step-by-step explanation:

The table

[tex]\begin{array}{lccccc}&\text{Nonsmoker}&\text{Occasional}&\text{Regular}&\text{Heavy}&\text{Total}\\\text{Men}&334&50&68&32&484\\\text{Women}&357&30&89&37&513\\\text{Total}&691&80&157&69&997\end{array}[/tex]

shows the smoking habits of a group of asthma sufferers.

a) The probability of getting a woman or nonsmoker is

[tex]P_1=\dfrac{513+334}{997}=\dfrac{847}{997}.[/tex]

b) The probability of getting a woman is

[tex]P_2=\dfrac{513}{997}.[/tex]

c) The probability of getting a man and a non smoker is

[tex]P_3=\dfrac{334}{997}.[/tex]

d) The probability of getting a woman and heavy smoker is

[tex]P_4=\dfrac{37}{997}.[/tex]

e) The probability of getting a man or heavy smoker is

[tex]P_5=\dfrac{484+37}{997}=\dfrac{521}{997}.[/tex]