Molar mass of NaNO3 is 84.9947 g/mol
Moles=given mass/molar mass
So, 44g/84.9947 g/mol=0.52mol.
Blessed!
Answer : The number of moles of [tex]NaNO_3[/tex] present in a given sample are 0.518 moles.
Explanation : Given,
Mass of [tex]NaNO_3[/tex] = 44.0 g
Molar mass of [tex]NaNO_3[/tex] = 84.99 g
Formula used :
[tex]\text{Moles of }NaNO_3=\frac{\text{Mass of }NaNO_3}{\text{Molar mass of }NaNO_3}[/tex]
Now put all the given values in this formula, we get:
[tex]\text{Moles of }NaNO_3=\frac{44.0g}{84.99g.mol}=0.518mole[/tex]
Therefore, the number of moles of [tex]NaNO_3[/tex] present in a given sample are 0.518 moles.
