Answer:
0.0985 M ≅ 0.1 M.
Explanation:
The concentration of the solution can be expressed by Molraity.
Molarity is the no. of moles of solute in 1.0 L of the solution.
M = (mass/molar mass)Na₂CO₃ x (1000/V of the solution)
mass of Na₂CO₃ = 2.61 g,
molar mass of Na₂CO₃ = 105.98 g/mol,
V of the solution = 250.0 mL.
M = (mass/molar mass)Na₂CO₃ x (1000/V of the solution) = (2.61 g / 105.98 g/mol) x (1000 / 250.0 mL) = 0.0985 M ≅ 0.1 M.
