Find the work w1 done on the block by the force of magnitude f1 = 95.0 n as the block moves from xi = -5.00 cm to xf = 4.00 cm .

Respuesta :

Answer;

= 8.55 Joules

Explanation;

Work done is the product of force and the distance moved by an object.

Work done = Force × distance

Force = 95 Newtons

Distance = X2 -X1

               = 4 - (-5)

               = 9 cm

Thus;

work done = 95 × 9/100

                  = 8.55 Joules

Lanuel

The work done on a block by the force exerted on it is equal to 8.55 Nm.

Given the following data:

  • Force = 95 Newton
  • Initial position = -5.00 cm
  • Final position = 4.00 cm

Conversion:

Initial position = -5.00 cm = [tex]\frac{5}{100} = 0.05\; meters[/tex]

Final position = 4.00 cm to m = [tex]\frac{4}{100} = 0.04\; meters[/tex]

To find the work done on a block by the force exerted on it:

First of all, we would determine the displacement of the block.

[tex]Displacement = x_f - x_i\\\\Displacement = 0.04 - (-0.05)\\\\Displacement = 0.04 + 0.05[/tex]

Displacement = 0.09 meters.

Mathematically, work done is given by the formula:

[tex]Work\;done = Force \times displacement[/tex]

Substituting the given parameters into the formula, we have;

[tex]Work\;done = 95 \times 0.09[/tex]

Work done = 8.55 Nm

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