Answer:
3.3 x 10⁷.
Explanation:
- For the reaction: 2CH₄(g) ⇄ C₂H₂(g) + 3H₂(g),
Kc = 0.135 at 1608 °C.
- To get Kp, we can use the relation:
Kp =Kc(RT)∧Δn.
R is the general gas constant = 8.314 J/mol.K.
T is the temperature of the vessel = 1608 °C + 273 = 1881.0 K.
Δn = no. of moles of gases in products - no. of moles of gases in the reactants = 4 - 2 = 2.
∴ Kp =Kc(RT)∧Δn = (0.135)[(8.314)(1881.0 K)]² = 3.3 x 10⁷.
