can someone please help me find the missing side?

Answer:
x ≈ 6.2
Step-by-step explanation:
To find x using trig. ratios we require to find the hypotenuse of the right triangle on the left.
From the right triangle on the right we can calculate the hypotenuse.
sin53° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{opp}{30}[/tex]
Multiply both sides by 30
opp = 30 × sin53° ≈ 24
Thus the length of the hypotenuse of the triangle on the left is 24, hence
cos75° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{x}{24}[/tex]
Multiply both sides by 24
x = 24 × cos75° ≈ 6.2
Answer:
6.20 units to the nearest hundredth.
Step-by-step explanation:
WE apply the trigonometry of a right angled triangle.
Consider the larger triangle where we can find the length of the side opposite to the 53 degree angle:
sin 53 = y / 30 (where y = length of the opposite side mentioned.)
y = 30 sin 53 = 23.96 units.
Now consider the smaller triangle where side y is the hypotenuse:
cos 75 = x / y
cos 75 = x / 23.96
x = 23.96 cos 75
= 6.20 units.