Gas mileage actually varies slightly with the driving speed of a car (as well as with highway vs. city driving). Suppose your car averages 33 miles per gallon on the highway if your average speed is 48 miles per hour, and it averages 29 miles per gallon on the highway if your average speed is 67 miles per hour.

a. What is the driving time for a 2600-mile trip if you drive at an average speed of 48 miles per hour? What is the driving time at 67 miles per hour?

The driving time at 48 miles per hour is _ hours.
(Type an integer or decimal rounded to two decimal places as needed.)

The driving time is at 67 miles per hour is hours.
(Round to two decimal places as needed.)

b. Assume a gasoline price of $3.05 per gallon. What is the gasoline cost for a 2600-mile trip if you drive at an average speed of 48 miles per hour?
What is the gasoline cost at 67 miles per hour?

The gasoline cost at 48 miles per hour is $:
(Round to two decimal places as needed.)

The gasoline cost at 67 miles per hour is $:
(Round to two decimal places as needed.)

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TaeKwonDoIsDead TaeKwonDoIsDead · Answer 1 · 2019-03-10T17:41:18+01:00

Answer:

a)

First part: "The driving time at 48 miles per hour is 54.17 hours."

Second part: "The driving time at 67 miles per hour is 38.81 hours."

b)

First part: "The gasoline cost at 48 miles per hour is $240.30"

Second part:

"The gasoline cost at 67 miles per hour is $273.45"

Step-by-step explanation:

a)

We use the equation [tex]D=RT[/tex] to solve this. Where D is the distance, R is the rate (speed), and T is the time.

First part:

The distance is 2600 miles (D) and the rate (R) is 48 mph, so time is:

[tex]D=RT\\2600=(48)T\\T=\frac{2600}{48}\\T=54.17[/tex]

"The driving time at 48 miles per hour is 54.17 hours."

Second part:

The distance is 2600 miles (D) and the rate (R) is 67 mph, so time is:

[tex]D=RT\\2600=(67)T\\T=\frac{2600}{67}\\T=38.81[/tex]

"The driving time at 67 miles per hour is 38.81 hours."

b)

First part:

At 48mph, the fuel consumption is 33 miles per gallon. The number of gallons needed is 2600 divided by 33:

Number of Gallons = [tex]\frac{2600}{33}=78.79[/tex]

Total cost @ 3.05 per gallon = 78.79*3.05=$240.30

"The gasoline cost at 48 miles per hour is $240.30"

Second part:

At 67 mph, the fuel consumption is 29 miles per gallon. The number of gallons needed is 2600 divided by 29:

Number of Gallons = [tex]\frac{2600}{29}=89.66[/tex]

Total cost @ 3.05 per gallon = 89.66*3.05=$273.45

"The gasoline cost at 67 miles per hour is $273.45"