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The isotope calcium-41 decays into potassium-41, with a half-life of 1.03 × 10^5 years. There is a sample of calcium-41 containing 5 × 10^9 atoms. How many atoms of calcium-41 and potassium-41 will there be after 4.12 × 10^5 years? How many calcium and how many potassium?​

Respuesta :

1.) Find The Number of Half Lives Passed:

[tex]= \frac{4.12*10^{5} \ years}{1.03*10^{5} \ years} =[/tex] half lives

2.) Calculate Number of Ca Atoms remaining:

[tex]A = A_{0} *2^{\frac{-t}{h}}\\A = 5*10^9 *2^{-4}\\\\A = 3.125*10^8[/tex] atoms left

3. Calculate Number of Potassium Atoms

Subtract the final number of Calcium atoms from the initial amount of calcium atoms.

[tex]5*10^9 - 3.125*10^8 = 4.6875*10^9[/tex] Atoms of Potassium

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