Answer:
[tex]sin(A)=\frac{48}{50}[/tex], [tex]cos(A)=\frac{14}{50}[/tex]
Step-by-step explanation:
Part a) Find the sin(A)
we know that
In the right triangle ABC
[tex]sin(A)=\frac{BC}{AB}[/tex] ----> the sine of angle (A) is the opposite side angle (A) divided by the hypotenuse
substitute the values
[tex]sin(A)=\frac{48}{50}[/tex]
Part b) Find the cos(A)
we know that
In the right triangle ABC
[tex]cos(A)=\frac{AC}{AB}[/tex] ----> the cosine of angle (A) is the adjacent side angle (A) divided by the hypotenuse
substitute the values
[tex]cos(A)=\frac{14}{50}[/tex]
