Answer:
Step-by-step explanation:
Given: The given expression is:
[tex]3x^2+4y^0(x-1)[/tex]
To find: The value of the expression at [tex]x=4[/tex] and [tex]y=5[/tex].
Solution: The given expression is:
[tex]3x^2+4y^0(x-1)[/tex]
Substituting [tex]x=4[/tex] and [tex]y=5[/tex] in the above expression, we have
=[tex]3(4)^2+4(5)^0(4-1)[/tex]
=[tex]3(16)+4(1)(3)[/tex]
=[tex]48+12[/tex]
=[tex]60[/tex]
thus, the value of the given expression is [tex]60[/tex].
The evaluated expression of 3x² + 4y⁰(x - 1) when x = 4 and y = 5 is 60.
Substitution simply means to put in place of another. Therefore, let's substitute the value of x and y in the mathematical expression.
Therefore,
y⁰ = 1
3x² + 4y⁰(x - 1)
3x² + 4y⁰(x - 1)
3x² + 4(x - 1)
3x² + 4x - 4
Therefore, when x = 4 and y = 5
3(4)² + 4(4) - 4
48 + 16 - 4 = 60
learn more on substitution here: https://brainly.com/question/18840615
