A sequence consists of the positive odd integers. What is the sum of the first 12 terms of the sequence?
A. 144
B. 169
C. 115
D. 121

Respuesta :

Answer:

A

Step-by-step explanation:

The sequence of positive odd numbers is

1, 3, 5, 7, ......

This is an arithmetic sequence with common difference d

d = 3 - 1 = 5 - 3 = 7 - 5 = 2

The sum to n terms of an arithmetic sequence is

[tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex][2a + (n - 1)d ]

where a is the first term

here a = 1, d = 2, n = 12, hence

[tex]S_{12}[/tex] = [tex]\frac{12}{2}[/tex][1 + (11 × 2) ]

                         = 6 [ 2 + (11 × 2) ]

                        = 6 × 24 = 144 → A

Answer:

A. 144.

Step-by-step explanation:

We have been given that a sequence consists of the positive odd integers. We are asked to find the sum of the first 12 terms of the sequence.

Our sequence would be: 1, 3, 5, 7, 9, 11, ....,

We will use sum of sequence formula to solve our given problem.

[tex]S_n=(\frac{a_1+a_n}{2})\cdot n[/tex], where,

[tex]a_1[/tex] = 1st term of sequence,

[tex]a_n[/tex] = nth term of sequence,

[tex]n[/tex] = Number of terms is the sequence.

Let us find nth term of sequence using formula:

[tex]a_n=a+(n-1)d[/tex], where,

d = Difference between two consecutive terms of sequence.

[tex]d=3-1=2[/tex]  

[tex]a_n=1+(12-1)2[/tex]

[tex]a_n=1+(11)2[/tex]

[tex]a_n=1+22[/tex]

[tex]a_n=23[/tex]

[tex]S_n=(\frac{1+23}{2})\cdot 12[/tex]

[tex]S_n=24\cdot 6[/tex]

[tex]S_n=144[/tex]

Therefore, the sum of 1st 12 terms of the sequence is 144 and option A is the correct choice.