Answer:
Option A.
The volume of the larger can is [tex]229.12\ in^{3}[/tex]
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube
Let
z-----> the scale factor
x-----> the volume of the larger can
y-----> the volume of the smaller can
so
[tex]z^{3}=\frac{x}{y}[/tex]
In this problem we have
[tex]z=2[/tex]
[tex]y=28.64\ in^{3}[/tex]
substitute and solve for x
[tex]2^{3}=\frac{x}{28.64}[/tex]
[tex]x=2^{3}*28.64=229.12\ in^{3}[/tex]
