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Rewrite each equation in the vertex form by completing the square. Then identify the vertex.

Rewrite each equation in the vertex form by completing the square Then identify the vertex class=

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Kamikazeminem

[tex]y = { x }^{2} - 10x + 22 \\ = {x}^{2} - 10x + 25 - 3 \\ = {(x - 5)}^{2} - 3 \\ V:(5, - 3)[/tex]

zainebamir540

Answer:

Vertex of equation is (5,-3).

Step-by-step explanation:

We have given a quadratic equation in standard form.

y  =  x²-10x+22

We have to rewrite given equation in vertex form.

y  = (x-h)²+k is vertex form of equation where (h,k) is vertex of equation.

We will use method of completing square to solve this.

Adding and subtracting  (-5)²  to above equation, we have

y  =  x²-10x+22+(-5)²-(-5)²

y  = x²-10x+(-5)²+22-(-5)²

y  = (x-5)²+22-25

y  = (x-5)²-3

Hence, vertex of equation is (5,-3).

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