Respuesta :

[tex]S\frac{O}{H} C\frac{A}{H} T\frac{O}{A}[/tex]

[tex]Sin=\frac{Opposite}{Hypotenuse} Cos=\frac{Adjacent}{Hypotenuse} Tan=\frac{Opposite}{Adjacent}[/tex]

7) You have the opposite. You need the adjacent.

[tex]Tan=\frac{Opposite}{Adjacent}[/tex]

[tex]Tan57=\frac{12}{x}[/tex]

[tex]x=\frac{12}{Tan57}[/tex]

x = 7.79289... =

7.8

8) You have the hypotenuse. You need the Opposite.

[tex]Sin=\frac{x}{Hypotenuse}[/tex]

[tex]Sin37=\frac{x}{13}[/tex]

x = sin37 × 13

x = 7.8235... =

7.8

9) You have the hypotenuse. You need the opposite.

[tex]Sin=\frac{x}{Hypotenuse}[/tex]

[tex]Sin59=\frac{x}{11}[/tex]

x = sin59 × 11

x = 9.4288.... =

9.4

10) You have the hypotenuse. You need the opposite.

[tex]Sin=\frac{x}{Hypotenuse}[/tex]

[tex]Sin53=\frac{x}{11}[/tex]

x = sin53 × 11

x = 8.7459.... =

8.7