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A man in a gym is holding an 8.0-kg object at arm's length, a distance of 0.55 m from his shoulder joint. What is the torque about his shoulder joint due to the object if his arm is held at 30° below the horizontal?

Respuesta :

Answer;

37.4 Nm

Explanation;

W = Mg

   = 8 × 9.81 m/s²

   = 78.5 N

Torque = Perpendicular Force × distance

             = 78.5 × Cos 30 × 0.55 m

             = 37.4 Nm

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